For a particle moving along the x-axis, x-t graph is as given as graph in figure. Mar the correct statement (s).
`(#BMS_V01_MAA_E01_052_Q01.png" width="80%">

Options

A. Initial velocity of the particle is zero.
B. For BC, acceleration is positive and for DE, acceleration is negative.
C. For EF, the acceleration is positive.
D. Velocity becomes zero three times in the motion.

Answer

A, C, D

Explanation

a,c,d. Velocity is given by the slope of the x-t graph. Here the slope
is zero at A and at peak of region CD and bottom most point of
EF.
For AB and EF, acceleration is positive. For these regions,
graph is concave up.
For BC and DE, acceleration is zero as here velocity is constant.
For CD, acceleration is negative as graph is concave down for
this region.