A particle is moving in a circular path of radius 1 m. under the action of a centripetal force, the speed `sqrt2pi ms^(-1)` of the particle is constant. Find the average of the velocity `("in" ms^(-1))` between A and B.

Answer

4

Explanation

`v_(av) = (rsqrt2)/(T//4) = (rsqrt2xx4v)/(2pir) = (2sqrt2v)/pi = (2sqrt(2)(sqrt2)pi)/pi = 4ms^(-1)`.