Figure shows a method for measuring the acceleration due to gravity. The ball is projected upward by a gun. The ball pases the electronic gates `1` and `2` as it rises and again as it falls. Each gate is connected to a separate timer. The first passage of the ball through each gate stars the corresponding timer, and the second passage through the same gate stops the timer. the time intervals `/_\t_(1)` and `/_\t_(2)` are thus measured. The vertical distance between the two gates is `d`. If `d=5m, /_\t_(1)=3s, /_\t_(2)=2s`, then find the measured value of acceleration due to gravity (in `m//s^(2)`)

Answer

8

Explanation

`1.5 = v_1/a`
`1 = v_2/a`
`5 = (v_(1)^(2) - v_(2)^(2))/(2a) , a = 8`
.