The hero of a stunt film fires `50 g` bullets form a machine gun, each at a speed of `1.0 km//s`. If he fires `20` bullets in `4s`, what average force does he exert against the machine gun during this period?
Text Solution
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The momentum of each bullet `(0.050kg)(1000m//s)=50kgm//s`. ltbr The gun is imparted this much of momentum by each bullet fired. Thus, the rate of change of momentum of the gun is `50 kg m/s xx20)/4s=250N`. In order to hold the gun, the hero must exert a force of `250 N` against the gun.
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