A ball of mass `1 kg` is attached to an inextensible string. The ball is released from the position shown in figure. Find the impulse imparted by the string to the ball immediately after the string becomes taut.
Text Solution
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The string will become taut when the particle will fall through a distance `2 m` in downward direction. So the required impulse `J="mu"=1xxsqrt(2xx10x2)=sqrt(40) kg m//s`
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