A mass `m` rests on a horizontal table. It is attached to a light inextensible string which passes over a smooth pulley and carries a mass `m` at the other end. If the mass `m` is raised vertically through a distance `h` and is then dropped, what is the speed with which the mass `2m` begins to rise?
Text Solution
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Velocity of the mass `m` just before string becomes tight. `v=sqrt(2gh)` ……….i Using impulse ` =` change in momentum For mass `2m` `J=2mv_(1)`……….ii For mass `m` `mv-J=mv_(1)` ………..iii Solving eqn i , ii and iii we get `v=sqrt((2gh)/3`
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