A `3.00 kg` steel hall strikes the wall with a speed of `10.0 m//s` at an angle of `60^(@)` with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for `0.200 s`, what is the average force exerted by the wall on the ball?

Explanation

`/_\vecp=vecF/_\t`
`/_\p_(y)=m(v_(fy)-v_(fy))=m(vcos6^(@))-mvcos60^(@)=0`
`/_\p_(x)=m(-vsin60^(@)-vsin60^(@)=-2mvsin60^(@)`
`=-2(3.00kg)(10.00m//s)(0.866)=-52.0kgm//s`

`F_(av)=(/_\p_x)//_\_t=(-52.0kgm//s)/(0.200s)=-260N`