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A force exerts an impulse Ion a particle...

A force exerts an impulse Ion a particle changing its speed from initial velocity `u` to final velocity `2u`. The applied force and the initial velocity are oppositely oriented along the same line. The work done by the force is

A

`3/2Iu`

B

`1/2Iu`

C

`Iu`

D

`2Iu`

Text Solution

Verified by Experts

The correct Answer is:
B

`I=m[2u-(-u)=3"mu"`
`W=1/2m[(2u)^(2)-u^(2)]=(3"mu"^(2))/2=(Iu)/2`
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