A glass sphere has a cavity inside it. whhen placed in water, it floats with `20` of its volume above the water surface. Find the volume of the cavity as a fraction of total volume (density of glass `=2.5g//"cc")`.
Text Solution
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Let the total volume of the sphere be `V`. Weight of the sphere `=` Buoyant force `implies` Mass of glass `xxg=80/100Vxx1xxg` `implies` Volume of galss `xxd=(80V)/100` If the volume of the cavity is `v`, then the volume of the galss is `(V-v)`, `(V-v)d=0.8Vimplies(V-v)/V=0.8/2.5` `implies(V-v)/V=0.32impliesv/V=0.68` Hence, volume of the cavity of `68%` of total volume. `implies` Volume of glass `xxd=(80V)/100` If the volume of the cavity is `v`, then the volume of te glass is `(V-v)`, `(V-v)d=0.8Vimplies(V-v)/V=0.8/2.5` `implies(V-v)/V=0.32impliesv/V=0.68` Hence, volume of the cavity is `68%` of the total volume.
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