A bent tube is lowered into a water stream as shown in figure. The velocity of the stream is `V_(1)`. The closed upper end is located at a height `h_(0) ` and has a small orifice. To what height `h` will the liquid get spurt? brgt
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`1/2rhov_(1)^(2)+P_(0)+0=1/2rhov_(2)^(2)+P_(0)+rhogh_(0)impliesV_(2)^(2)=V_(1)^(2)=2gh_(0)` If the liquid reaches a height `h` then `V_(2)^(2)=2gh`, `implies2gh, V_(1)^(2)-2gh_(0)implies h=(V_(1)^(2))/(2g)=h_(0)`
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