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A liquid flows through a horizontal tube...

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section `A_(1)` and `A_(2)` are `v_(1)` and `v_(2)` respectively. The difference in the levels of the liquid in the two vertical tubes is `h`. Then

A

the volume of the liquid flowing through the tube in unit time is `A_(1)v_(1)`

B

`v_(2)-v_(1)=sqrt(2gh)`

C

`v_(2)^(2)-v_(1)^(2)=2gh`

D

the energy per unit mass of the liquid is the same in both sections of the tube

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`(P_(1))/(rho)+(v_(1)^(2))/2=(P_(2))/(rho)+(v_(2)^(2))/2`
`P_(1)-P_(2)=(rho)/2(v_(2)^(2)-v_(1)^(2))`
But
`P_(1)-P_(2)=rhogh=(rho)/2(v_(2)^(2)-v_(1)^(2))`
or `v_(2)^(2)-v_(1)^(2)=2gh`
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Knowledge Check

  • A liquid flows through a horizontal tube as shown in figure. The velocities of the liquid in the two sections, which have areas of cross-section A_(1) and A_(2) and v_(1) and v_(2) respectively. The differnece in the levels of the liquid in the two vertical tubes is h . then

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    B
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    C
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    D
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