Home
Class 11
PHYSICS
A liquid flows through a horizontal tube...

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section `A_(1)` and `A_(2)` are `v_(1)` and `v_(2)` respectively. The difference in the levels of the liquid in the two vertical tubes is `h`. Then

A

the volume of the liquid flowing through the tube in unit time is `A_(1)v_(1)`

B

`v_(2)-v_(1)=sqrt(2gh)`

C

`v_(2)^(2)-v_(1)^(2)=2gh`

D

the energy per unit mass of the liquid is the same in both sections of the tube

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`(P_(1))/(rho)+(v_(1)^(2))/2=(P_(2))/(rho)+(v_(2)^(2))/2`
`P_(1)-P_(2)=(rho)/2(v_(2)^(2)-v_(1)^(2))`
But
`P_(1)-P_(2)=rhogh=(rho)/2(v_(2)^(2)-v_(1)^(2))`
or `v_(2)^(2)-v_(1)^(2)=2gh`
Promotional Banner

Topper's Solved these Questions

  • FLUID MECHANICS

    CENGAGE PHYSICS|Exercise Assertion-Reasoning|8 Videos

  • FLUID MECHANICS

    CENGAGE PHYSICS|Exercise Linked Comprehension|43 Videos

  • FLUID MECHANICS

    CENGAGE PHYSICS|Exercise Single Correct|95 Videos

  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS|Exercise Integer|2 Videos

  • GRAVITATION

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|1 Videos

Similar Questions

Explore conceptually related problems

A liquid flows through a horizontal tube as shown in figure. The velocities of the liquid in the two sections, which have areas of cross-section A_(1) and A_(2) and v_(1) and v_(2) respectively. The differnece in the levels of the liquid in the two vertical tubes is h . then

From a horizontal tube with area of cross-section A_(1) and A_(2) as shosn in fiugre liquid is flowing in the level of the liauid in the two veritcal tunes is h.

An incompressible, non-viscous liquis of density r flows through a horizontal tube as shown below. The flow condition is steady. Area of cross section at A and B are a_(1) and a_(2) respectively. The height difference of liquid in two tubes inserted at A and B is h.

An incompressible liquid flows through a horizontal tube as shown in the figure. Then the velocity 'v' of the fluid is:

Water flows through a horizontal tube as shown in figure. If the difference of heights of water colun in the vertical tubes is 2 cm and the area of cross section at A and B are 4cm^2 and 2cm^2 respectively, find the rate of flow of water across any section.

An incompressible liquid flows through a horizontal tube LMN as shown in the figure. Then the velocity V of the liquid throught he tube N is:

The mass of the liquid flowing per second per unit area of cross section of the tube is proportional to P^(x) and v^(y) , where P is the pressure difference and v is the velocity , then the relation between x and Y is

A horizontal thin tube of length 2L completely filled with a liquid of density delta rotates about a vertical axis passing through one of its end and along the diameter of its side face with an constant angular velocity omega . Two vertical thin long tubes are fitted with the horizontal tube to measure the pressure difference between points A and B which are at same horizontal level as shown. Neglect viscous forces and surfaces tension of liquid. The difference in the heights (h) of the liquid column in the two vertical thin tubes is :

A liquid flows through a pipe of non-uniform cross-section. If A_(1) and A_(2) are the cross-sectional areas of the pipe at two points, the ratio of velocities of the liquid at these points will be

Fig, shows a U-tube of uniform cross-sectional area A accelerated with acceleration a as shown. If d is the seperation between the limbs. Then the difference in the levels of the liquid in the U-tube is

Knowledge Check

  • A liquid flows through a horizontal tube as shown in figure. The velocities of the liquid in the two sections, which have areas of cross-section A_(1) and A_(2) and v_(1) and v_(2) respectively. The differnece in the levels of the liquid in the two vertical tubes is h . then

    A
    `v_(2)^(2)-v_(1)^(2) = 2 gh`
    B
    `v_(2)^(2)+v_(1)^(2) = 2 gh`
    C
    `v_(2)^(2)-v_(1)^(2) = gh`
    D
    `v_(2)^(2)+v_(1)^(2) = gh`

  • An incompressible liquid flows through a horizontal tube as shown in the figure. Then the velocity 'v' of the fluid is:

    A
    3.0 m/s
    B
    1.5 m/s
    C
    1.0 m/s
    D
    2.25 m/s

  • An incompressible liquid flows through a horizontal tube LMN as shown in the figure. Then the velocity V of the liquid throught he tube N is:

    A
    `1ms^(-1)`
    B
    `2ms^(-1)`
    C
    `4.5ms^(-1)`
    D
    `6ms^(-1)`