If the container filled with liquid gets accelerated horizontally or vertically, pressure in liquid gets changed. In liquid (`a_(y)`) for calculation of pressure, effective `g` is used. A closed box horizontal base `6 m` by `6 m` and a height `2m` is half filled with liquid. It is given a constant horizontal acceleration `g//2` and vertical downward acceleration `g//2`.
The angle of the free surface with the horizons is equal to

Options

A. `30^@`
B. `tan^(-1) 2/3`
C. `tan^(-1)` `1/3`
D. `45^@`

Answer

D

Explanation

`(dy)/(dx)=(a_(x))/(a_(y)+g)=(g//2)/(-g//2+g)=1`
(Effective acceleration due to gravity will be `g-a=g//2`)
`:. theta=45^@`