If the container filled with liquid gets accelerated horizontally or vertically, pressure in liquid gets changed. In liquid (`a_(y)`) for calculation of pressure, effective `g` is used. A closed box horizontal base `6 m` by `6 m` and a height `2m` is half filled with liquid. It is given a constant horizontal acceleration `g//2` and vertical downward acceleration `g//2`.
Water pressure at the bottomof centre of the box is equal to (atmospheric pressure `=10^(5)N//m^(2)` density of water `=1000 kg//m^(3),g=10m//s^(2)`)

Options

A. `1.1MPa`
B. `0.11MPa`
C. `0.101MPa`
D. `0.011MPa`

Answer

B

Explanation

`P=P_(a)+rhogh=10^(5)-1000x10xx1`
`=(10^(5)+10^(4))N//m^(2)=0.11MPa`