if `tan(theta/2)=cosectheta-sintheta` then `cos^2(theta/2)`

If tan\ theta/2=cosectheta-sintheta, then- a. sin^2\ theta/2=2sin^2\ 18^@ b. cos2theta+2costheta+1=0 c. sin\ theta/2=4sin^2\ 18^@ d. cos2theta+2costheta-1=0

If tan\ theta/2=cosectheta-sintheta, then- a. sin^2\ theta/2=2sin^2\ 18^@ b. cos2theta+2costheta+1=0 c. sin\ theta/2=4sin^2\ 18^@ d. cos2theta+2costheta-1=0

If tan(theta/2)=cosec theta-sintheta then the numerical balue of "cos"^(2)theta/2=

Prove that sintheta(cosectheta-sintheta)=cos^2theta .

Prove: (cos e c\ theta+sintheta)(cos e c\ theta-sintheta)=cot^2theta+cos^2theta

If cos^2theta-sintheta=1/4 then sintheta=?

Prove that (((1+cot theta +tan theta)(sintheta-costheta))/(sec^3theta -cosec^3theta)) = (sin^2theta cos^2theta)

If sin theta=cos theta then 2tan theta+cos^(2)theta=

frac(sintheta [(1-tantheta) tan theta+sec^2 theta])((1-sintheta) tantheta(1+tan theta) (sec theta+tantheta)) =?

Prove that (cos theta-sintheta)/(cos theta+sintheta)=sec 2 theta-tan 2theta .