`(sin^3theta+sin3theta)/(sintheta)+(cos^3theta-cos3theta)/(costheta)=`

(sin^(3)theta+sin3theta)/(cos^(3)theta-cos3theta)

(sin3theta-cos3theta)/(sintheta+costheta)+1 =

(sin ^ (3) theta + sin3 theta) / (sin theta) + (cos ^ (3) theta-cos3 theta) / (cos theta) =

(sin 3theta)/(sin theta)-(cos 3theta)/(cos theta)=

Prove the following identities : (cos^(3)theta+sin^(3)theta)/(costheta+sintheta)+(cos^(3)theta-sin^(3)theta)/(costheta-sintheta)=2

The value of (cos^(3)theta+sin^(3)theta)/(costheta+sintheta)+(cos^(3)theta-sin^(3)theta)/(costheta-sintheta) is equal to

Prove that (cos^3theta+sin^3 theta)/(cos theta+sin theta)+(cos^3 theta-sin^3 theta)/(cos theta-sin theta)=2

( sin 3 theta )/( sin theta ) -(cos 3 theta )/( cos theta )=

Prove that (sin theta+ sin 2theta + sin 3 theta)/(costheta+cos2theta+cos3theta)=tan 2 theta

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .