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Assuming the earth of to be a uniform sp...

Assuming the earth of to be a uniform sphere of radius `6400 kg` and density `5.5 g//c.c.`, find the value of `g` on its surface`G=6.66xx10^(-11)Nm^(2)kg^(-2)`

Text Solution

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Here `R=6400xx10^(3)m=6.4xx10^(6)m`
`rho=5.5g//c.c.=5.5xx10^(3)kg//m^(3)`
Now `g=(GM)/(R^(2))=G/R^(2)xx4/3piR^(3)xxrho`
`=4/3piGR rho`
`=4/3xx22/7xx6.66xx10^(-11)xx6.4xx10^(6)xx5.5xx10^(3)`
`9.82ms^(-2)`
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