a. Find the height from the earth's surface where `g` will be `25%` of its value on the surface of earth `(R=6400km)`. b. Find the percentage increase in the value of `g` at a depth `h` from the surface of earth.
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a. At a height `h` above the earth's surface we have `g'=g(R/(R+h))^(2)impliesg/4=g(R/(R+h))^(2)impliesR/(R+H)=1/2` `implies h=R=6400km` b. At a depth `h` below earth's surface, we have `g'=g(1-h/R)implies(g')/g=1-4/6400` `(g-g')/g=4/6400implies(/_\g)/g=1/16` `:. %` age `=(/_\g)/gxx100=1/6%` increase
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