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What would be the time period of rotatio...

What would be the time period of rotation of earth so that the bodies at the equator would weight `40%` of their actual weight?

Text Solution

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Gravity at the equator is given by
`g'="g" ((1-omega^(2)R)/g)`
Apparent weight at the equator
`W'=mg(1=(omega^(2)R)/g)`
`implies40/100mgmg(1-(omega^(2)R)/g)`
`implies omega=sqt(0.6/r)implies(2pi)/omega=2pisqrt(R/(0.6g))=2pisqrt((6400xx10^(3))/(0.6xx10))`
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