A projectile is fired vertically from the earth's surface with an initial speed of `10 km//s`. Neglecting air drag, how high above the surface of earth will it go?
Text Solution
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`1/2mv^(2)-(GMm)/R=(GMm)/(R+h)` (as final `KE=0`) Substituting `h=2.5xx10^(7)m,` we get the desired result.
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