The radius of a planet is twice that of the earth but its average density is the same. If the escape speed at the planet and at the earth are `v_(p)` and `v_(e)`, respectively, then prove that `v_(p)=2v_(e)`

Explanation

To solve the problem, we need to derive the escape speed for both the planet and the Earth and then compare them.

### Step-by-Step Solution:

1. **Understanding Escape Speed**:
The escape speed \( v \) from a celestial body is given by the formula:
\[
v = \sqrt{\frac{2GM}{R}}
...