A satellite moves in a circular orbit around the earth at height `(R_(e))//2` from earth's surface where `R_(e)` is the radius of the earth. Calculate its period of revolution. Given `R = 6.38 xx 10^(6) m`.

Explanation

To calculate the period of revolution of a satellite moving in a circular orbit around the Earth at a height of \( \frac{R_e}{2} \) from the Earth's surface, we can follow these steps:

### Step 1: Determine the distance from the center of the Earth to the satellite
The radius of the Earth is given as \( R_e = 6.38 \times 10^6 \, \text{m} \). The height of the satellite above the Earth's surface is \( h = \frac{R_e}{2} \).

So, the distance \( R \) from the center of the Earth to the satellite is:
\[
R = R_e + h = R_e + \frac{R_e}{2} = R_e \left(1 + \frac{1}{2}\right) = \frac{3}{2} R_e
...