Home
Class 11
PHYSICS
A small satellite revolves around a plan...

A small satellite revolves around a planet in an orbit just above planet's surface. Taking the mean density of the planet `8000 kg m^(-3)` and `G = 6.67 xx 10^(-11) N //kg^(-2)`, find the time period of the satellite.

Text Solution

Verified by Experts

`T=2pisqrt((R^(3))/(GM))=2pisqrt({(R^(3))/((G4/3piR^(3)rho))})=sqrt((3pi)/(Grho))`
`=sqrt((3xx3.14)/(6.67xx10^(-11)xx8000))~~4202s`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    CENGAGE PHYSICS|Exercise Subjective|15 Videos

  • GRAVITATION

    CENGAGE PHYSICS|Exercise Single Correct|122 Videos

  • GRAVITATION

    CENGAGE PHYSICS|Exercise Exercise 6.3|16 Videos

  • FLUID MECHANICS

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|1 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS|Exercise Integer|9 Videos

Similar Questions

Explore conceptually related problems

A small satellite revolves round a planet in an orbit just above planet's surface. Taking the mean density of planet as rho , calculate the time period of the satellite.

A satellite revolves round a planet in an orbit just above the surface of planet. Taking G=6.67xx10^(-11) Nm^(2) kg^(-2) and the mean density of the planet =8.0xx10^(3) kg m^(-3) , find the period of satellite.

A satellite revolves around a planet of mean density 4.38 xx 10^(3)kg//m^(3) , in an orbit close to its surface. Calculate the time period of the satellite. Take, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

A satellite revolves in an orbit close to the surface of a planet of mean density 5.51 xx 10^(3) kg m^(-3) . Calculate the time period of satellite. Given G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

A satelite revolves around a planet in an elliptical orbit. Its maximum and minimum distances from the planet are 1.5xx10^(7) m and 0.5xx10^(7) m respectively. If the speed of the satellite at the farthest point be 5xx10^(3) m/s, calculate the speed at the nearest point.

If the period of revolution of an artificial satellite just above the earth be T second and the density of earth be rho , kg//m^(3) then (G = 6.67 xx 10^(-11) m^(3)//kg . "second"^(2) )

An artificial satellite revolves round the earth at a height of 1000 km . The radius of the earth is 6.38xx10^(3)km . Mass of the earth 6xx10^(24)kg,G=6.67xx10^(-11)Nm^(2)kg^(-2) . Find the orbital speed and period of revolution of the satellite.

The period of moon around the earth is 27.3 days and radius of the orbit is 3.9 xx 10^(5) km . G=6.67 xx 10^(-11) Nm^(-2)kg^(-2) , find the mass of the earth.