The gravitational potential energy of body of mass 'm' at the earth's surface -`mgR_(e)`. Its gravitational potential energy at a height `R_(e)` from the earth's surface will be (here `R_(e)` is the radius of the earth)

Options

A. `mgR`
B. `0.67mgR`
C. `-(mgR)/2`
D. `0.33mgR`

Answer

C

Explanation

`PE=(-GM)/(2R)` (at height `R`)
`=-(GMR_(m))/(2R^(2))=-1/2mgR`