If a man at the equator would weigh (3//...

If a man at the equator would weigh `(3//5)`th of his weight, the angular speed of the earth is

`sqrt(2/5 g/R)`

`sqrt(g/R)`

`sqrt(R/g)`

`sqrt(2/5 R/g)`

Text Solution

Verified by Experts

The correct Answer is:

`3/5mg=mg=mRomega^(2)`
`=omega^(2)=g-3/5impliesomega=sqrt(2/5g/R)`

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