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The value of overset(pi//2)underset(0)in...

The value of `overset(pi//2)underset(0)int x^(10) sin x" dx"`, is then the value of `mu_(10)+90mu_(8)`, is

A

`10(pi/2)^(3)`

B

`10(pi/2)^(9)`

C

`pi/2`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B

Given, `l_(10)=int_(0)^(pi//2)x^(10)sinx dx`
`=[-x^(10)cosx]_(0)^(pi//2)10x^(9).cos xdx`
`=0+[10x^(9)sinx]_(0)^(pi//2)-int_(0)^(pi//2)90x^(8)sin xdx`
`=10((pi)/(2))^(9)-90l_(8)`
`rArr" "l_(10)+90l_(8)=10((pi)/(2))^(9)`
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Knowledge Check

  • The value of int_(0)^(pi//2) x^(10) sin x" dx" , is then the value of mu_(10)+90mu_(8) , is

    A
    `9((pi)/(2))^(8)`
    B
    `((pi)/(2))^(9)`
    C
    `10((pi)/(2))^(9)`
    D
    `9((pi)/(2))^(9)`
  • The value of the integral overset(pi)underset(0)int log(1+cos x)dx is

    A
    `(pi)/(2)log2`
    B
    `-pi log2`
    C
    `pi log2`
    D
    none of these
  • If I_(10) = int_0^(pi//2)x^(10) sin x dx then the value of I_(10) + 90I_6 is

    A
    `9(pi/2)^(6)`
    B
    `(pi/2)^(9)`
    C
    `10(pi/2)^(9)`
    D
    `9(pi/2)^(9)`
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