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Two bodies with masses M(1) and M(2) are...

Two bodies with masses `M_(1)` and `M_(2)` are initially at rest and a distance `R` apart. Then they move directly towards one another under the influence of their mutual gravitational attraction. What is the ratio of the distances travelled by `M_(1)` to the distance travelled by `M_(2)`?

A

`(M_(1))/(M_(2))`

B

`(M_(2))/(M_(1))`

C

`1`

D

`1/2`

Text Solution

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The correct Answer is:
To find the ratio of the distances traveled by two bodies with masses \( M_1 \) and \( M_2 \) under mutual gravitational attraction, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the System**: - We have two masses, \( M_1 \) and \( M_2 \), initially at rest and a distance \( R \) apart. - As they move towards each other due to gravitational attraction, we need to analyze their motion. 2. **Defining Distances**: - Let \( X_1 \) be the distance traveled by mass \( M_1 \) and \( X_2 \) be the distance traveled by mass \( M_2 \). - The total distance between them remains constant, so we have: \[ X_1 + X_2 = R \] 3. **Center of Mass Consideration**: - The center of mass of the system does not move since the only forces acting are internal (gravitational forces between the two masses). - The position of the center of mass \( R_{cm} \) can be defined as: \[ R_{cm} = \frac{M_1 \cdot R_1 + M_2 \cdot R_2}{M_1 + M_2} \] - Here, \( R_1 \) and \( R_2 \) are the distances from a reference point to each mass. 4. **Setting Up the Equation**: - Let \( R_1 \) be the initial distance of \( M_1 \) from the center of mass and \( R_2 \) be the initial distance of \( M_2 \) from the center of mass. - We can express the distances in terms of \( X_1 \) and \( X_2 \): \[ R_1 - X_1 \text{ (for } M_1\text{)} \quad \text{and} \quad R_2 - X_2 \text{ (for } M_2\text{)} \] 5. **Applying the Center of Mass Condition**: - Since the center of mass does not move, we can write: \[ M_1(R_1 - X_1) = M_2(R_2 - X_2) \] - Expanding this gives: \[ M_1 R_1 - M_1 X_1 = M_2 R_2 - M_2 X_2 \] 6. **Using the Initial Condition**: - From the initial condition, we know that: \[ R_1 M_1 = R_2 M_2 \] - Thus, we can substitute \( R_1 M_1 \) and \( R_2 M_2 \) into our equation, leading to: \[ -M_1 X_1 + M_2 X_2 = 0 \] - Rearranging gives: \[ M_1 X_1 = M_2 X_2 \] 7. **Finding the Ratio**: - Dividing both sides by \( X_2 \) and \( M_1 \): \[ \frac{X_1}{X_2} = \frac{M_2}{M_1} \] ### Final Result: The ratio of the distances traveled by \( M_1 \) to the distance traveled by \( M_2 \) is: \[ \frac{X_1}{X_2} = \frac{M_2}{M_1} \]

To find the ratio of the distances traveled by two bodies with masses \( M_1 \) and \( M_2 \) under mutual gravitational attraction, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the System**: - We have two masses, \( M_1 \) and \( M_2 \), initially at rest and a distance \( R \) apart. - As they move towards each other due to gravitational attraction, we need to analyze their motion. ...
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