The value of `g` at a particular point is `10 m s^(-2)`. Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of `g` at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be

Options

A. `5ms^(-2)`
B. `10ms^(-2)`
C. `3ms^(-2)`
D. `20 ms^(-2)`

Answer

B

Explanation

`F=(GMm)//R^(2)=mg`
As the mass remains the same and radius i.e. distance from the centre is also same, therefore `g` will remain the same i.e, `10 ms^(-2)`