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The solution of the differential equati...

The solution of the differential equation
`x( x-y) (dy)/(dx) = y(x+y)` , is

A

`x/y+log (xy)=C`

B

`y/x +log (xy)=C`

C

` x/y + y log x = C`

D

` x/y + x log y = C`

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The correct Answer is:
To solve the differential equation \( x(x-y) \frac{dy}{dx} = y(x+y) \), we will follow these steps: ### Step 1: Rearranging the Equation First, we can rearrange the given equation to isolate \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = \frac{y(x+y)}{x(x-y)} \] ### Step 2: Substituting \( y = vx \) Next, we will use the substitution \( y = vx \), where \( v \) is a function of \( x \). Then, we differentiate \( y \) with respect to \( x \): \[ \frac{dy}{dx} = v + x \frac{dv}{dx} \] ### Step 3: Substitute \( y \) and \( \frac{dy}{dx} \) Substituting \( y = vx \) and \(\frac{dy}{dx}\) into the rearranged equation gives: \[ v + x \frac{dv}{dx} = \frac{vx(x + vx)}{x(x - vx)} \] This simplifies to: \[ v + x \frac{dv}{dx} = \frac{v(x^2 + vx)}{x(x - vx)} = \frac{v(x + v)}{(1 - v)} \] ### Step 4: Simplifying the Equation Now, we can simplify the equation further: \[ x \frac{dv}{dx} = \frac{v(x + v)}{(1 - v)} - v \] \[ x \frac{dv}{dx} = \frac{v(x + v - v + v^2)}{(1 - v)} = \frac{v(x + v^2)}{(1 - v)} \] ### Step 5: Separating Variables Now, we can separate the variables: \[ \frac{(1 - v)}{v(x + v^2)} dv = \frac{dx}{x} \] ### Step 6: Integrating Both Sides Integrate both sides: \[ \int \frac{(1 - v)}{v(x + v^2)} dv = \int \frac{dx}{x} \] This can be split into two integrals: \[ \int \left( \frac{1}{v} - \frac{1}{x + v^2} \right) dv = \log |x| + C \] ### Step 7: Solving the Integrals The left side can be integrated: \[ \log |v| - \frac{1}{2} \log |x + v^2| = \log |x| + C \] ### Step 8: Back Substituting for \( v \) Recall that \( v = \frac{y}{x} \). Substitute back: \[ \log \left|\frac{y}{x}\right| - \frac{1}{2} \log |x + \left(\frac{y}{x}\right)^2| = \log |x| + C \] ### Step 9: Final Rearrangement Rearranging gives us the implicit solution of the differential equation: \[ \frac{y}{x} - \frac{1}{2} \log |x + \frac{y^2}{x^2}| = \log |x| + C \] ### Final Solution Thus, the solution of the differential equation is: \[ y = x \left( \text{some function of } x \right) \]

To solve the differential equation \( x(x-y) \frac{dy}{dx} = y(x+y) \), we will follow these steps: ### Step 1: Rearranging the Equation First, we can rearrange the given equation to isolate \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = \frac{y(x+y)}{x(x-y)} \] ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-DIFFERENTIAL EQUATION-MHT CET Corner
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