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Find the differential equation of the fa...

Find the differential equation of the family of circles whose centres lie on `X`-axis.

A

` (d^(2)y)/(dx)^(2)+((dy)/(dx))^(2)+1=0`

B

` y (d^(2)y)/(dx^(2))+((dy)/(dx))^(2)-1=0`

C

` y (d^(2)y)/(dx^(2))-((dy)/(dx))^(2)-1=0`

D

` y (d^(2)y)/(dx^(2))+((dy)/(dx))^(2)+1=0`

Text Solution

Verified by Experts

The correct Answer is:
d

The equation of family of circles having centre on X - axis is ` x^(2) +y^(2) - 2ax = 0`
On differentiating , we get` 2x + 2y (dy)/(dx) - 2a = 0`
Again , on differentiating, we get
` 2+2 [ y (d^(2)y)/(dx^(2))+((dy)/(dx))^(2)] = 0 rArr`
` y (d^(2)y)/(dx^(2)) +((dy)/(dx))^(2) + 1 = 0`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-DIFFERENTIAL EQUATION-MHT CET Corner
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