A satellite is seen after every `8` hours over the equator at a place on the earth when its sense of rotation is opposite to the earth. The time interval after which it can be seen at the same place when the sense of rotation of earth and satellite is same will be:

Options

A. `8h`
B. `12h`
C. `24h`
D. `6h`

Answer

C

Explanation

Given `g=(2pi)/(omega_(1)+omega_(2))=(2pi)/((2pi)/(T_(1))+(2pi)/(T_(2)))`
`implies T_(1)=24h` for the earth
`impliesT_(2)=12h` (`T_(2)` being the time period of the satellite, it will remain the same as the distance from the centre of the earth remains constant)
`implies T=(2pi)/(omega_(2)+omega_(1))=(2pi)/((2pi)/(T_(1))-(2pi)/(T_(2))=24h`