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A geostationary satellite is orbiting th...

A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height of 2.5 R from the surface of the earth is …… hours.

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The correct Answer is:
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According to Kepler's law,
`(T_(1)^(2))/(T_(2)^(2))=(R_(1)^(2))/(R_(2)^(2))`
`implies (24xx24)/(T_(2)^(2))=(6xx6xx6xxR^(3))/(2.5xx2.5xx2.5xxR^(3))`
`implies T_(2)^(2)=(24xx24xx2.5xx2.5xx2.5)/(6xx6xx6)=6.45h`
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