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Ferric oxide crystallizes in a hexagonal...

Ferric oxide crystallizes in a hexagonal close - packed array of oxide ions with two of every three octahedral holes occupied by ferric ions . Derive the formula of ferric oxide .

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Given ferric oxide crystallises in a hexagonal close packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions .
In hexagonal close - packed arrangement there is one octahedral hole for each atom .
If the number of oxide ions `(O^-2)` per unit cell ,then the number of `Fe^(+3)` ions = `2 //3 xx` octahedral holes .
`= 2//3 xx 1 = 2//3`
The formula of the compound = `F_(2//3) O_(1)`
(or) `Fe_(2) O_(3)` .
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