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Determine the amount of CaCl(2) (i=2.47)...

Determine the amount of `CaCl_(2)` (i=2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at `27^(@)C`.

Text Solution

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Van't Hoffs equation
Osmotic pressure `(pi)=" i CRT"`
i = 2.47
V = 2.5 lit
R = `0.0821" lit. atm.k"^(-1)."mol"^(-1)`
`T = 27+273=300" K"`
`pi = 0.75" atm"`
`pi=i((n_(B))/(V))"RT"`
`n_(B)=(pi"V")/("iRT")=(0.75xx2.5)/(2.47xx0.0821xx300)=0.0308`
The amount of `CaCl_(2)` dissolved `=n_(B)xxm_(B)`
`=0.0308xx111=3.42" gms"`
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