How are `XeF_(2)` and `XeF_(4)` prepared ? Give their structures.

Explanation

Xenon forms the binary fluorides `XeF_(2),XeF_(4),XeF_(6)` as follows. These are formed by direct combination of Xe and `F_(2)`.
`underset(("Xenon in excess"))(Xe+F_(2))underset("1 bar")overset(673" K")toXeF_(2)`
`underset((1:5" ratio"))(Xe+2F_(2))underset(4" bar")overset(873"K")toXeF_(4)`
Structure of `XeF_(2)` :
1) In `XeF_(2)` central atom is 'Xe'.
2) 'Xe' undergoes `sp^(3)d` hybridisation in it's `1^(st)` excited state

3) Shape of molecule is linear.
4) Xe form tow `sigma`. bonds with two fluorines. `" ""Fe"-underset("xx")overset("xx")(Xe)-"F"`
b) Structure of `XeF_(4)` :
1) Central atom in `XeF_(4)` is 'Xe'.
2) Xe undergoes `sp^(3)d^(2)` hybridisation in it's `2^(nd)` excited. state.

3) Shape of the molecule is square planar with bond angle `90^(@)` and bond length `1.95Å`.

4) Xe-forms four `sigma`-bonds by the overlap of `sp^(3)d^(2)-2p_(z)` (F) orbitals.