Which is a stronger reducing agent `Cr^(2+) or Fe^(2+)` and why ?

Explanation

`Cr^(2+)` is a stronger reducing agent than `Fe^(2+)`. The `E^(@)` values are
`E_(Cr^(3+)//Cr^(2+))^(@)=-0.41 V and E_((Fe^(3+)//Fe^(2+))^(0)=0.77 V`
Transition `Cr^(2+) rarr Cr^(3+)` is easier than
`(3d^(4))" "(3d^(3))`
`Fe^(2+) rarr Fe^(3+)` because in latter, an electron is removed from the paired orbital (difficult)
`(3d^(6))" "(3d^(5))`
Therefore, `Cr^(2+)` is stronger reducing agent (itself gets oxidised easily) than `Fe^(2+)`