Two sitar string A and B playing the note 'Ga' are slightly out of tune and produce betas of frequency 6 Hz.The tension in the string A is slightly reduced and the beat frequency is found to reduceto 3Hz.If the origianl frequency of Ais 324 Hz. What is the frequency of B ?

Explanation

Let original frequency of sitar string A be `n_(a)` & original frequency of sitar B be `n_(b)`.
As number of beats `//` sec = 6
`:.n_(b) =n_(a)+-6 =324 +- 6 = 330 ` (or) 318 Hz.
When tension in A is reduced , it's frequency reduces`( :. n prop sqrt(T))`.
As number of beats `//` sec decreases to 3 therefore, frequency of B `= 324 -6`
`318 Hz`