Light from a point source in air falls on a spherical glass surface. If `mu = 1.5`, and radius of curvature `= 20 cm`, the distance of light source from the glass surface is `100 cm` , at what position will the image be formed ? (NCERT Solved Example)

Explanation

We use the relation given by Eq. `(h_(2))/(upsilon)-(h)/(u)=(h_(2)-h_(1))/(R).` Here
`u=-100cm, upsilon=?. R = +20cm, n_(1)=1, and n_(2)=1.5`. We then have
`(1.5)/(upsilon)+(1)/(100)=(0.5)/(20)`
`or upsilon=+100cm`