In a meter bridge the balance point is found to be at 39.5 cm from the end A, when the resistor Y is of `12.5 Omega`. Determine the resistance of x. why are the connections between resistors in a wheatstone or meter bridge made of thick copper strips?

Explanation

Here `l = 39.5 cm, R = X = ?, S = Y = 12.5 Omega`
As `S = (100 - l)/(l) xx R`
`:. 12.5 = (100 - 39.5)/(39.5) xx X`
or `X = (12.5 xx 39.5)/(60.5) = 8.16 Omega`
Thick copper strips are used to minimise resistance of the connections which are not accounted in the formula.