The resistance of the platinum wire of a platinum resistance thermometer at the ice point is `5 Omega` and at steam point is `5.39 Omega`. When the thermometer is inserted in a hot bath, the resistance of the platinum wire is `5.795 Omega`. Calculate the temperature of the bath.

Explanation

`R_(0) = 5 Omega, R_(100) = 5.23 Omega` and `R_(t) = 5.795 Omega`
Now, `t = (R_(t) - R_(0))/(R_(100) - R_(0)) xx 100, R_(t) = R_(0) (1 + alpha t)`
`= (5.795 - 5)/(5.23 - 5) xx 100`
`= (0.795)/(0.23) xx 100 345.65^(@)C`