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A current-carrying circular loop lies on...

A current-carrying circular loop lies on a smooth horizontal plane. Can a uniform magnetic field be set up in such a manner that the loop turns around it self (i.e. turns about the vertical axis).

Text Solution

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Torque `(tau)=vecMxxvecB=I vecA xx vecB" (M = n I A)"`
where I is current, `vecA` is area vector. `vecB` is magnetic field. Area vector `vecA` acts normal to the loop, so torque `vectau` cannot act along the vertical axis. The magnetic field is not set up to turn the loop around it self.
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