A bar magnet of magnetic moment `1.5 JT^(-1)` lies aligned with the direction of a uniform magnetic field of 0.22 T.
magnetic moment : (i) normal to the field direction, (ii) opposite to the field direction ?What is the torque on the magnet in cases (i) and (ii) ?

Explanation

Torque `r = mB sin theta`
(i) Here `theta = 90^(@), r = 1.5 xx 0.22 sin 90^(@) = 0.33 Nm`
(ii) Here `theta = 180^(@), r = 1.5 xx 0.22 sin 180^(@) = 0`