The primary of a transformer with primary to secondary turns ratio of 1 : 2, is connected to an alternator of voltage 200 V. A current of 4A is flowing though the primary coil. Assuming that the transformer has no losses, find the secondary voltage and current are respectively.

Explanation

Given that `(N_(1))/(N_(2))=(1)/(2)`
`E_(1)=200V, i_(1)=4A`
(i) Transformer ratio `= (E_(2))/(E_(1))=(N_(2))/(N_(1))`
`(E_(2))/(200)=(2)/(1)`
`E_(2)=400 V`
(ii) `(N_(2))/(N_(1))=(i_(1))/(i_(2))`
`(2)/(1)=(4)/(i_(2))`
`i_(2)=2A`