A `60 mu F` capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.

Explanation

Given, capacitance of the capacitor C
`= 60 mu F`
`= 60xx10^(-6)F`
`V_("rms")=110V`
Frequency of AC supply f = 60 Hz
Capacitive reactance
`X_(C )=(1)/(2pi fC)=(1)/(2xx3.14xx60xx60xx10^(-6))`
`= 44.23 Omega`
The rms value of current in the circuit
`V_("rms")=(V_(rms"))/(X_(C ))=(110)/(44.23)=2.49 A`