Home
Class 12
PHYSICS
Figure shows a series LCR circuit connec...

Figure shows a series LCR circuit connected to a variable frequency 230 V source. `L = 5.0 H, C = 80 mu F, R = 40 Omega`.

Obtain the impedance of the circuit and the amplitude of current at the resonanting frequency.

Text Solution

Verified by Experts

Given, the rms value of voltage `V_("ims")=230 V`
Inductance L = 5H
Capacitance `C = 80 mu f = 80xx10^(-6)F`
Resistance `R = 40 Omega`
At the resonant frequency, `X_(L)=X_(C )`
So, impedance of the circuit Z = R.
`therefore` Impedance `Z = 40 Omega`
The rms value of current in the circuit
`I_("rms")=(V_("rms"))/(Z)=(230)/(40)=5.75 A`
Amplitude of current `I_(0)=I_("rms")sqrt(2)`
`= 5.75xx sqrt(2)`
`= 8.13 A`
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise ADDITIONAL EXERCISES|35 Videos

  • ALTERNATING CURRENT

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise LONG ANSWER QUESTIONS|1 Videos

  • ANDHRA PRADESH MARCH-2019

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise SECTION-C|3 Videos

Similar Questions

Explore conceptually related problems

Figure shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80 mu F, R = 40 Omega . Determine the source frequency which drives the circuit in resonance.

Figure shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80 mu F, R = 40 Omega . Determine the rms potential drops across the three elements of the circuit. Show that the potential drop across the LC combination is zero at the resonating frequency.

Obtain the resonant frequency omega_(r ) of a series LCR circuit with L = 2.0H. C = 32 mu F and R = 10 Omega . What is the Q-value of this circuit ?

A series LCR circuit with L = 0.12 H, C = 480 nF, R = 23 Omega is connected to a 230 V variable frequency supply. What is the Q - factor of the given circuit ?