A parallel plate capacitor in the figure made of circular plates each of radius R=6.0 cm has a capacitance C=100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad `s^(-1)` .

Is the conduction current equal to the displacement current ?

Explanation

Yes, `I=I_(d)` where I is steady d.c. or a.c. . This is shown below
`I_(d)=epsi_(0)(d(phi_(E)))/(dt)=epsi_(0)* (d)/(dt)(EA)`
`I_(d)=epsi_(0)=A.(dE)/(dt)=A(d)/(dt) ((theta)/(epsi_(0)A))`
`I_(d)=epsi_(0)Axx(1)/(epsi_(0)A)*(d theta)/(dt)=(d theta)/(dt)=I`