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Calculate the ionization energy for a li...

Calculate the ionization energy for a lithium atom.

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For `3^(Li^(7))` atom, `Z=3, n=2 [because Li =1s^(2) 2s^(1)]`
`E_(n)=(13.6Z^(2))/(n^(2))eV`
`=(13.6xx(3)^(2))/(4)=30.6 eV`
`therefore` Ionization energy of Lithium =30.6 eV.
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