The wavelength of first member of Balmer series is `6563 Å`. Calculate the wavelength of second member of Lyman series.

Explanation

`(1)/(lamda)=R((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`
For `1^(st)` member of Balmer series,
`(1)/(6563)=R((1)/(2^(2))-(1)/(3^(2)))`
`(1)/(6563)=(5R)/(36)" "rarr(1)`
For `2^(nd)` member of Lyman series,
`(1)/(lamda^(1))=R((1)/(1^(2))-(1)/(3^(2)))`
`(1)/(lamda^(1))=(8R)/(9)" "rarr(2)`
`((1))/((2))rArr(lamda^(1))/(6563)=(5R)/(36)xx(9)/(8R)`
`lamda^(1)=(5)/(32)xx6563`
`therefore lamda^(1)=1025.5 Å`