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Consider the D - T reaction (deuterium -...

Consider the D - T reaction (deuterium - tritium fusion)
`._(1)^(2)H+ ._(1)^(3)H to ._(2)^(4)He + n`
Calculate the energy released in MeV in this reaction from the data :
`m(._(1)^(2)H)=2.014102 u`
`m(._(1)^(3)H)=3.016049 u`

Text Solution

Verified by Experts

Hint : Kinetic energy required for one fusion event = average thermal kinetic energy available with the interacting particles = 2(3kt/2) , k = Boltzman's constant, T = absolute temperature.
For the process `._(1)H^(2)+ ._(1)H^(3)+ ._(2)He^(4)+ n + Q`
`Q = [m(._(1)H^(2))+m(._(1)H^(3))+m(._(2)He^(4))-m_(n)]xx931 MeV`
`= (2.014102+3.016049-4.002603 - 1.00867)xx931 MeV`
`= 0.018878xx931=17.58 MeV`
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