Calculate and compare the energy released by a. fusion of 1.0 kg of hydrogen deep within Sun and b. the fission of 1.0 kg of `.^(235)U` in a fission reactor.

Explanation

In sun, four hydrogen nuclei fuse to form a helium nucleus with the release of 26 MeV energy.
`therefore` Energy released by fusion of 1 kg of hydrogen `= (6xx10^(23)xx26)/(4)xx10^(3)MeV`
`E_(1)=39xx10^(26)MeV`
As energy released in fission of one atom of `._(92)U^(236)=200 MeV`
Energy released in fission of 1kg of `._(92)U^(238)`
`= (6xx10^(23)xx1000)/(235)xx200 MeV`
`E_(2)=5.1xx10^(26)MeV`
`(E_(1))/(E_(2))=(39xx10^(26))/(5.1xx10^(26))=7.65`
i.e., Energy released in fusion is 7.65 times the energy released in fission.