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For a CE-transistor amplifier,the aurdio...

For a CE-transistor amplifier,the aurdio signal across the collectoed resistance of 2 `k Omega ` is 2V. Suppose the current amplification factor of the transistoris 100, find the input signal voltage and base current, if the base resistance is `1 k Omega`.

Text Solution

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Given, collector resistance `R __("output") = 2 K Omega = 2000 Omega `
Current amplification factor of the transistor `beta _(AC) = 100`.
Audio signal voltage `V_("output") = 2V `
Input ( base) resistance `R_("input") = 1 K Omega = 1000 Omega `
`:.` Voltage gain `A_(V ) = ( v_("output"))/(v_("input"))= beta_(ac) . ( R_("output"))/(R_("input"))`
`:.`Input signal voltage `V_("input")= ( V_("output"))/(beta_(ac).((R_("output"))/(R_("input"))))= (2)/( 100((2000)/(1000)))= 0.01V `
Base ( input ) current `I_(B) = ( V_("input"))/( R_("input"))= (0.01 )/(1000) xx 10 xx 10^(-6) =10 mu A `
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